SUBNETTING KELAS B CIDR 20 DAN 23

1. 128.25.0.0/23

  A. 256-2^=256-2^=256-2=254

       255.255.254.0

  B. 256-254=2

  C. 2^=512

  D. 2^-2=2^-2=512-2=510 HOST

  F. 2^=2^=128 BIT

  E. 0,2,4,6,8,10,12.....254

  SUBNET= 128.25.0.0

  HOST I= 128.25.0.1

  HOST T= 128.25.1.254

  BROADCAST= 128.25.1.255

  510 TU NET= I FE 

  FE TU DEC= 254

  I TU DEC= 1

 2. 128.25.0.0/20

  IIIIIIII. IIIIIIII. IIII0000. 00000000

  A. 256-2^=256-2^=256-16=240 

       255.255.240.0

  B. 256-240=16

  C. 2^=4096

  D. 2^=2=2^-2=4096-2=4094 HOST

  F. 2^=2^=16 BIT

  E. 0,16,32,48,64.....240

  SUBNET= 128.25.0.0

  HOST I= 128.25.0.1

  HOST T= 128.25.15.254

  BROADCAST= 128.25.15.25.5